question_answer 38)

The time required for 10% completion of a first order reaction at 298 K is equal to that required for its 25% completion at 308 K. If the value of A is 3.56 x 109, calculate k at 318 K and F and Ea. 

Answer:

Let in time 't ' the reaction is 10%, complete at 298 K At 308 K, in time 't ' the reaction is 25%. Complete = 76666.9 J mol?1 = 76.7kJ  mol?1 = 9.5514 ? 12.59 = ?3.0386 log k = ?3 ? 0.0386 = ?3 ? 1 + 1 ? 0.386 = ?4 + 0.9614 log k = k = antilog