question_answer 17)

Given the standard electrode potential. K+ /K = – 2.93V, Ag+/Ag = 0.80 V. Hg2+/Hg = 0.79 V Mg2+/Mg = – 2.37 V, Cr3+/Cr = – 0.74 V Arrange these metals in their increasing order of reducing power.  

Answer:

Lower the reduction potential more the tendency to get oxidized and thus more will be reducing power. Hence increasing order of reducing power of metal is Ag < Hg < Cr < Mg < K.