question_answer 27)

How much charge is required for the following reduction of (i) 1 mol of Al3+ to Al. (ii) 1 mol of Cu2+ to Cu. (iii) 1 mol of  to Mn2+

Answer:

(i) For reduction of 1 mole of  charge needed = 3F For reduction of 1 mole of Al3+, electricity needed = 3 × 96500 C = 289500 C (ii)   For reduction o 1 mole of Cu2+, charge needed = 2F         For reduction of 1 mole of Cu2+, electricity needed = 2 × 96500 C = 193000 C (iii) For reduction of 1 mole of  electricity needed = 5 F. For reduction of 1 mole of  electricity needed = 5 × 96500 C = 482500 C