question_answer 5)

Calculate the emf of the cell in which t-following reaction takes place                 Ni(s) + 2Ag+ (0.002M) Ni2+ (0.160 M) + 2Ag(s)                 Given that E°cell = 1.05 V.

Answer:

In this cell reaction, nickel acts as anode while silver acts as cathode. According to Nernst equation = 1.05 ? 0.0295 log (4 × 10)4 = 1.05 ? 0.0295 × 4.6020 = 1.05 ? 0.1357 = 0.9143 V.