Answer:
tert-Butyl
bromide readily loses ion to form stable
fert-butyl carbocation. Therefore, it undergoes reaction by mechanism which occurs in two
steps. In the first step, tert-butyl carbocation is formed. This
step is slow and hence is the rate determining step of the
reaction. In the second step, the tert-butyl carbocation is readily attacked
by ion to form tert-butyl
alcohol.
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