Answer:
On reacting with sodium ethoxide in ethanol, the H-atom from p-carbonatom is eliminated. This is called p-elimination. Simultaneously,elimination of halogen atom from a-carbon takes place.
(i) 1-bromo-1-methylcyclohexane has two -hydrogen atoms.
So, two products will be formed.
NoteSaytzeff's rule: The product is preferred in which thecarbon atoms joined by double bond are more alky] substituted oralkylated.
(ii)
(iii)
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