(III)
(a) I < II < III (b)II < I <
III
(c)III < II < I (d)I < III
<II
Answer:
(c) More the number of electron-donating 
groups
at o- and p-positions w.r.t. the Cl atom, less reactive is the compound. Thus,
option (c), i.e. III < II < I is correct.
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