question_answer 36)

 Based on solute-solvent interactions, arrange the following in order of increasing solubility in n-octane and explain : Cyclohexane, KCI, CH­3OH, CH3CN  

Answer:

(i) Cyclohexane and n-octane both are non-polar and are completely miscible. (ii) KCI is an ionic compound and is not soluble in n-octane. (iii) CH3OH and CH3CN both are polar but CH3CN is less polar than CH3OH. Since the solvent is non-polar, CH3CN will dissolve more than CH3OH in n-octane. Thus, the increasing order of solubility of the given compounds will be : KCI < CH3OH < CH3CN < Cyclohexane