Answer:
Step I. Calculation of van't Hoff factor
(i) for the acid
...(i)
K kg mol-1, M2 = 78 g
mol-1, w2 = 19.5 g
w1 = 500 g = 0.5 kg
Put these values in equation (i)
= 1.0753
Step II. Calculation of van't Hoff factor
Suppose degree of dissociation at the given
concentration is .
CH2FCOOH CH2FCOO?
+ H+
Initial conc. 1 mot
L?1 0 0
No. of moles
after dissociation (1 ? )
Total no. of moles after dissociation
= 1 +
or
Step III. Calculation of dissociation
constant for the acid
CH2FCOOH CH2 FCOO-
+ H+
Initial colic. C mol L?1 0 0
At equilibrium C(1 ? ) C C
But C (molality) = 0.5 m
Ka = C2 = (0.5)
(0.0753)2
= 2.835 x 10-3
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