question_answer 46)

Vapour pressure of water at 293 K is 17.535 mm Hg. Calculate the vapour pressure of water at 293 K when 25 g of glucose is dissolved in 450 g of water.

Answer:

Here, p0 = 17.535 mm, w2 = 25 g, w1 = 450 g, For solute (glucose, C6H12O6), M2 = 180 g mol-1, For solvent. (H2O), M1 = 18 g mol-1 Applying Raoult's law, for dilute solutions,   or Substituting the given values, we get