Answer:
No. of moles of liquid A (nA)
No. of moles of liquid B
Mole fraction of A
in the solution (xA)
Mole
fraction of B in the solution (xB)
= (1 ? xA) = 1 ? 0.114 = 0.886
Also, given
Applying Raoult's law,
??
(i)
= 443 torr ...
(ii)
PTotal = 0.114
or (Vapour pressure
of pure liquid A)
Substituting this value in equation (i), we
get
PA (Vapour pressure of A in
solution)
= 0.114 x 280.7 torr = 32 torr
You need to login to perform this action.
You will be redirected in
3 sec