12th Class Chemistry Solutions / विलयन

  • question_answer 7)
    Henry's law constant for CO2 in water is 1.67 x 108 Pa at 298 K. Calculate the quantity of CO2 in 500 mL of soda water when packed under 2.5 atm CO2 pressure at 298 K.

    Answer:

    KH = 1.67 x 108 Pa Applying Henry's law,   = 1.517 x 10-3 i.e.,    gas is not much soluble in water i.e.,           so it is neglected in the denominator) For 500 mL of soda water, water present i.e.,                        or  27.78 x 1.517 x 10?3 = 42.14 x 10-3 mole Mass of CO2 = 42.14 x 10-3 x 44 g = 1.8548  


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