question_answer 40)

Find a point on the curve y = (x – 2)2 at which the tangent is parallel to the chord joining (2, 0) and (4, 4) 

Answer:

Let P (h, k) be the required point. A lies on             y = (x ? 2)2                    ? (1)          K = (h ? 2)2                    ?.(2)       Diff. (1) w.r.t. x       m = slope of tangent to (1)                   Now slope of the chord joining the points (2, 0) and (4, 4) is             Acc. to Questions       m = m1                          Required point is (3,1). Remark : The above problems can also be solved using L.M.V. theorem.