Answer:
Let 
we have 
A12 =
(?1)1+2 (2+10) = ?12
A13 =
(?1)1+3 (0 +6) = 6
A21 =
(?1)2+1 (?1 ?0) = 1
A22 =
(?1)2+2 (1 + 4) = 5
A23 =
(?1)2+3 (0 ? 2) = 2
A31 =
(?1)3+1 (?5 ?6) = ?11;
A32 =
(?1)3+2 (5 ? 4) = ?1
A33 =
(?1)3+3 (3 + 2) = 5
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