question_answer 68)

Solve the system of equations using matrix method 2x + 3y + 3z = 5; x – 2y + z = –4; 3x – y – 2y = 3,  

Answer:

The given system of equations can be expressed as       AX = B, where                           and                  = 2 (4 + 1) ? 3 (?2 ? 3)                     + 3 (?1 + 6)       = 10 + 15 + 15 = 40 0       Therefore A is non-singular so A?1 exists and given system has a unique solutions.          A11 = 5; A12 = 5; A13 = 5       A21 = 3; A22 = ?13; A23 = 11       A31 = 9; A32 = 1; A33 = ?7                               Now AX = B                               On equating, we get x = 1, y = 2, z = ?1.