Answer:
Given
f : be an
invertible function
is both
one-one and onto.
there exists
a function
such that
Let
y,
be such that
is one-one,
Also,
x = f?1(y) exists for
.
Hence
f?1 is both one-one and onto.
exists.
Now
is the
inverse of f?1.
which
is proved.
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