Answer:
Given
Injective
: Let x1 and x2 are two distinct elements of R.
Case
? I : When
and
Case-II
: When
and
Case
IV : When x1< 0 and x2
and
Hence
in all the above cases
f is one-one.
Surjective
: Let y be any element of R.
y = f(x)
(i) When
y + xy = x
(ii) When
y ? xy =x
y = xy + x
Hence f is onto.
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