question_answer 2)

The work function of caesium metal is 2.14 eV. When light of frequency 6 x 1014 Hz is incident on the metal surface, photoemission of electrons occurs. What is the (a) maximum kinetic energy of the emitted electrons, (b) stopping potential, and (c) maximum speed of the emitted photoelectrons ?  

Answer:

Here                                 Also (a) Maximum   kinetic   energy   of photoelectrons is K.E. = hv - W  (b) Stopping potential is given by (c)