question_answer 14)

Two tiny spheres carrying charges  and  are located 30 cm apart. Find the potential and electric field:                 (a) at a point 10 cm from this mid-point in a plane normal to the line and passing through the mid-point.  

Answer:

(a) (i) Potential, V = VA + VB                                                         = 2.4 × 105V.                 (ii) Electric field, E = EB ? EA                                                  towards 1.5  charge.                 (b) (i) In this case distance AQ becomes  i.e. 0.18 m.                 Now Potential, V = VA + VB                                                 = 2 × 105 V. (ii) Electric Field,                                 Here                 Where                 and                                 =  4.167 × 105 NC?1                                 = 6.944 × 105 NC?1                 Using (i), (ii), and (iv),                                 For direction,                                 we get tan                   Resultant electric field is inclined at an angle  with AB.