Answer:
(a) Let the five wires A,
B, C, D and E be perpendicular to the plane of paper at locations as shown in
Fig. 3(EP).11.
Resultant
magnetic field induction at O due to current through all the five wires is = 0
(as magnetic field induction due to five wires will be represented by various
sides of a closed pentagon in one order, lying in the plane of paper).
(b)
Total Magnetic field induction at O due to currents through the wires B, C, D
and E is equal and opposite to the magnetic field induction at O due to current
through wire A.
Magnetic field induction at
O due to current through wire A is
acting to AO towards right.
Magnetic field induction at
O due to currents through the wires B, C, D and E is = , acting to AO towards left.
(c)
If current in wire A is reversed, then total magnetic field induction at O
=
mag. field induction due to wire A + mag. field induction due to wires B, C, D
and E
= (acting AO towards left) + (acting AO towards left)
= acting AO towards left.
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