Answer:
Let
be the output
which appears at the first operation of NOR gate.
Then
...(1)
This output
is fed into an other NOR gate so that
Now using
Boolean Algebra,
![]()
(using
eqn. (1))
= A + B
which is an OR operation.
the
circuit is an OR gate and its truth lable is
A
B
Y
0
0
0
1
0
1
0
1
1
1
1
1
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