Answer:
Let be the output
which appears at the first operation of NOR gate.
Then ...(1)
This output
is fed into an other NOR gate so that
Now using
Boolean Algebra,
(using
eqn. (1))
= A + B
which is an OR operation.
the
circuit is an OR gate and its truth lable is
A
B
Y
0
0
0
1
0
1
0
1
1
1
1
1
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