Answer:
(a) Step 1. Molar mass of sucrose,
or 342 g = 1 mole of sucrose
3,42 g = 0.01 mole of sucrose
1
mole of sucrose contains
0-atoms = 11 x 6.022 x1023 atoms
0.01
mole of sucrose will contain 0-atoms
= 0.01 x 11 x 6.022x 1023 atoms = 6.6242 x 1022
Step 2. 18 g of water = 1 mole of
water 1 mole of water contains
0-atoms = 6.022 x 1023 atoms
Step 3. By adding the number of I-atoms present in
3.42 g of sucrose and 18 g of water we get 6.022x 1023 + 6.6242 x 1022
= 1022 (60,22 +6.6242) = 66.844 x 1022 = 6.68x 1023
atoms
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