question_answer 26)

A ball thrown up vertically returns to the thrower after 6 s. Find (a) the velocity with which it was thrown up, (b) the maximum height it reaches, and (c) its position after 4 s.  

Answer:

                Here, time of ascent = time of descent, (a) From   (b) From   (c)  ball is at maximum height. From (below the top)