8th Class Mathematics Data Handling

  • question_answer 7)
                    A group of 360 people were asked to vote for their favourite season from the three seasons rainy, winter and summer.
    Season No. of Votes
    Summer 90
    Rainy 120
    Winter 150
    (i) Which season got the most votes? (ii) Find the central angle of each sector. (iii) Draw a pie chart to show this information.

    Answer:

                    (i) Winter season got the most votes. (ii) Central angle of winter sector \[=\frac{\begin{align}   & \text{Number of people who vote} \\  & \text{                        for}\,\text{winter}\,\text{season} \\ \end{align}}{\text{Total}\,\text{number}\,\text{of}\,\text{people}}\,\ \times {{360}^{\text{o}}}\] \[=\frac{150}{360}\times 360{{}^{\text{o}}}\times {{150}^{\text{o}}}\] Central angle of summer sector \[\text{=}\frac{\begin{align}   & \text{Number of people who vote} \\  & \text{                 }\,\,\,\,\,\,\,\,\,\,\,\text{for}\,\text{summer}\,\text{season} \\ \end{align}}{\text{Total}\,\text{number}\,\text{of}\,\text{people}}\,\ \text{ }\!\!\times\!\!\text{ 36}{{\text{0}}^{\text{o}}}\] \[=\frac{90}{360}\times {{360}^{\text{o}}}={{90}^{\text{o}}}\] Central angle of rainy sector \[\text{=}\frac{\begin{align}   & \text{Number of people who vote } \\  & \,\,\,\,\,\,\,\,\,\,\text{                        for}\,\text{rainy}\,\text{season} \\ \end{align}}{\text{Total}\,\text{number}\,\text{of}\,\text{people}}\,\ \text{ }\!\!\times\!\!\text{ 36}{{\text{0}}^{\text{o}}}\] \[=\frac{120}{360}\times {{360}^{\text{o}}}={{120}^{\text{o}}}\]                 (iii)
    Season People who Voted for it In fraction Central angle
    Winter 150 \[\frac{5}{12}\] \[\frac{5}{12}\] of \[{{360}^{\text{o}}}={{150}^{\text{o}}}\]
    Summer 90 \[\frac{1}{4}\] \[\frac{1}{4}\] of \[{{360}^{\text{o}}}={{90}^{\text{o}}}\]
    Rainy 120 \[\frac{1}{3}\] \[\frac{1}{3}\] of \[{{360}^{\text{o}}}={{120}^{\text{o}}}\]
    Pie chart


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