8th Class Mathematics Direct and Inverse Proportions

  • question_answer 15)                 A farmer has enough food to feed 20 animals in his cattle for 6 days. How long would the food last if there were 10 more animals in his cattle?

    Answer:

                    Suppose that the food would last for \[x\] days. We have the following table.

    Number of animals 20 \[20+10=30\]
    Number of days 6 \[x\]
    We note that more the number of animals, lesser will be the number of days for which the food will last. Therefore, this is a case of inverse proportion. So,          \[20\times 6=30\times x\] \[\Rightarrow \]               \[x=\frac{20\times 6}{30}\] \[\Rightarrow \]               \[x=4\]                 Hence, the food would last for 4 days.

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