Answer:
Suppose that the food would last for \[x\] days. We have the following table.
We note that more the number of animals, lesser will be the number of days for which the food will last. Therefore, this is a case of inverse proportion. So, \[20\times 6=30\times x\] \[\Rightarrow \] \[x=\frac{20\times 6}{30}\] \[\Rightarrow \] \[x=4\] Hence, the food would last for 4 days. Number of animals 20 \[20+10=30\] Number of days 6 \[x\]
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