• # question_answer 5)                 A photograph of a bacteria enlarged 50,000 times attains a length of 5 cm as shown in the diagram. What is the actual length of the bacteria? If the photograph is enlarged 20,000 times only, what would be its enlarged length?

Actual length of the bacteria $=\frac{5}{50000}\,cm$ $=\frac{1}{10000}\,cm={{10}^{-4}}\,cm$ More the number of times a photograph of a bacteria is enlarged, more the length attained. So, the number of times a photograph of a bacteria is enlarged and the length attained are directly proportional to each other. So,          $\frac{{{x}_{1}}}{{{y}_{1}}}=\frac{{{x}_{2}}}{{{y}_{2}}}$ $\Rightarrow$               $\frac{50000}{5}=\frac{20000}{{{y}_{2}}}$ $\Rightarrow$               $50000\,{{y}_{2}}=5\times 20000$ $\Rightarrow$               ${{y}_{2}}=\frac{5\times 20000}{50000}$ $\Rightarrow$               ${{y}_{2}}=2$ Hence, its enlarged length would be 2 cm.