question_answer 17)

Find: (i) \[\frac{1}{4}\]of        (a) \[\frac{1}{4}\]                             (b) \[\frac{3}{5}\]                             (c) \[\frac{4}{3}\]              (ii) \[\frac{1}{7}\]of       (a) \[\frac{2}{9}\]                             (b) \[\frac{6}{5}\]                             (c) \[\frac{3}{10}\].

Answer:

                (i) (a) \[\frac{1}{4}\]of \[\frac{1}{4}=\frac{1}{4}\times \frac{1}{4}=\frac{1\times 1}{4\times 4}=\frac{1}{16}\]                 (b) \[\frac{1}{4}\]of \[\frac{3}{5}=\frac{1}{4}\times \frac{3}{5}=\frac{1\times 3}{4\times 5}=\frac{3}{20}\]                 (c) \[\frac{1}{4}\]of \[\frac{4}{3}=\frac{1}{4}\times \frac{4}{3}=\frac{1\times 4}{4\times 3}=\frac{4}{12}\] \[=\frac{4\div 4}{12\div 4}=\frac{1}{3}\]                 (ii) (a) \[\frac{1}{7}\]of \[\frac{2}{9}=\frac{1}{7}\times \frac{2}{9}=\frac{1\times 2}{7\times 9}=\frac{2}{63}\]                 (b) \[\frac{1}{7}\]of \[\frac{6}{5}=\frac{1}{7}\times \frac{6}{5}=\frac{1\times 6}{7\times 5}=\frac{6}{35}\] (c) \[\frac{1}{7}\]of \[\frac{3}{10}=\frac{1}{7}\times \frac{3}{10}=\frac{1\times 3}{7\times 10}=\frac{3}{70}\]