question_answer 27)

Find: (i) \[\frac{7}{3}\div 2\]                   (ii) \[\frac{4}{9}\div 5\]                  (iii) \[\frac{6}{13}\div 7\]                               (iv) \[4\frac{1}{3}\div 3\] (v) \[3\frac{1}{2}\div 4\]                               (vi) \[4\frac{3}{7}\div 7\]             

Answer:

                (i) \[\frac{7}{3}\div 2=\frac{7}{3}\times \frac{1}{2}=\frac{7\times 1}{3\times 2}=\frac{7}{6}=1\frac{1}{6}\]                 (ii) \[\frac{4}{9}\div 5=\frac{4}{9}\times \frac{1}{5}=\frac{4\times 1}{9\times 5}=\frac{4}{45}\]                 (iii) \[\frac{6}{13}\div 7=\frac{6}{13}\times \frac{1}{7}=\frac{6\times 1}{13\times 7}=\frac{6}{91}\]                 (iv) \[4\frac{1}{3}\div 3=\frac{13}{3}\div 3=\frac{13}{3}\times \frac{1}{3}=\frac{13}{9}=1\frac{4}{9}\]                 (v) \[3\frac{1}{2}\div 4=\frac{7}{2}\div 4=\frac{7}{2}\times \frac{1}{4}=\frac{7\times 1}{2\times 4}=\frac{7}{8}\]                 (vi) \[4\frac{3}{7}\div 7=\frac{31}{7}\div 7=\frac{31}{7}\times \frac{1}{7}=\frac{31\times 1}{7\times 7}=\frac{31}{49}\]