6th Class Mathematics Fractions

  • question_answer 23)
    Compare the fractions and put an appropriate sign. (a) \[=\frac{1}{5}\] (b) \[=\frac{2}{5}\] (c) \[=\frac{3}{5}\] (d) \[\frac{1}{5}+\frac{2}{5}=\frac{1+2}{5}=\frac{3}{5}\]

    Answer:

    (a) We have, \[\therefore \] Here, denominators are same of both fractions. So, fraction having smaller numerator will be smaller. \[\frac{5}{5}\] \[=\frac{3}{5}\] (b) We have, \[=\frac{2}{5}\] Here, numerators are same of both fractions. So, fraction having smaller denominator will be greater. \[1-\frac{3}{5}=\frac{5-3}{5}=\frac{2}{5}\] \[\therefore \] (c) We have, \[=\frac{2}{6}\] Here, denominators are same of both fractions. So, fraction having smaller numerator will be smaller. \[=\frac{3}{6}\] \[=\frac{5}{6}\] (d) We have, \[=\frac{2}{6}+\frac{3}{6}=\frac{2+3}{6}=\frac{5}{6}\] Here, numerators are same of both fractions. So, fraction having smaller denominator will be greater. \[\therefore \] \[\frac{3}{5}\frac{3}{7}\]


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