Answer:
Given, length of the table-top = 2 m and breadth of the table-top = 1m 50 cm = 1m + 50 cm \[=1m+50\times \frac{1}{100}m\] \[\left[ \because 1cm=\frac{1}{100}m \right]\] \[=1m+\frac{50}{100}m=1m+0.50m=3.50m\] \[\therefore \] Area of the table-top = Length\[\times \]Breadth = 2 m \[\times \] 1.50 m= 3sqm Hence, the area of the table-top is 3 sq m.
You need to login to perform this action.
You will be redirected in
3 sec