question_answer 24)

                The lateral surface area of a hollow cylinder is \[4224\,c{{m}^{2}}\]. It is cut along its height and formed a rectangular sheet of width 33 cm. Find the perimeter of rectangular sheet?

Answer:

                Lateral surface area of the hollow cylinder \[=4224\,c{{m}^{2}}\] \[\Rightarrow \]               Area of the rectangular sheet \[=4224\,c{{m}^{2}}\] \[\Rightarrow \]               Length \[\times 33=4224\] \[\Rightarrow \]               Length \[=\frac{4224}{33}\] \[\Rightarrow \]               Length = 128 cm \[\therefore \] Perimeter of the rectangular sheet = 2(Length + Breadth) = 2(128 + 33) cm = 2(161) cm = 322 cm Hence, the perimeter of the rectangular sheet is 322 cm.