question_answer 52)

Three tankers contain 403 Litres 434 Litres and 465 Litres of diesel, respectively. Find the maximum capacity of a container, that can measure the diesel of the three containers exact number of times.

Answer:

                Here, maximum quantity of container will be equal to the HCF of 403, 434 and 465. 13 403 2 434 3 465 31 31 7 217 5 155 1 31 31 31 31 1 1 1 Prime factorisation of    \[403=13\times \] Prime factorisation of \[434=2\times 7\times \] Prime factorisation of \[465=3\times 5\times \] Common factor of 403, 434 and 465 is 31. \[\therefore \] Maximum capacity of container = HCF of 403, 434, and 465 = 31 Litres