question_answer 22)

Repeat Question 6, if \[{{l}_{4}}\]happens to be a diameter.

Answer:

                To construct the perpendicular bisector of diameter \[{{l}_{1}}\] we use the following steps Step I Draw a circle with C as centre and radius 3.4 cm. Step II Draw diameter AB of the circle (a diameter is a chord passing through the centre of the circle). Step III With A as centre, using compasses, draw an arc with radius more than half of the length of \[{{l}_{1}},{{l}_{2}},{{l}_{3}},{{l}_{4}},{{l}_{5}}\]. Step IV With the same radius and with B as centre, draw another arc using compasses. Let it cuts the previous arc at M and N. Step V Join \[{{l}_{6}}\] It cuts \[{{l}_{1}},{{l}_{2}},{{l}_{3}},{{l}_{4}},{{l}_{5}}\] at C.                Therefore, \[{{l}_{6}}\] is the perpendicular bisector of \[{{l}_{1}},{{l}_{2}},{{l}_{3}},{{l}_{4}}\] Also, \[{{l}_{5}}\] passes through the centre C of the circle. Hence, perpendicular bisector of diameter passes through the centre of the circle.