question_answer 27)

Draw a right angle and construct its bisector.                  

Answer:

                Here, firstly draw an angle of measure \[{{90}^{o}}\] and then construct its bisector. For this, we use the following steps: Step I Draw \[{{l}_{1}}\]of any length. Place the centre of the protractor at A and the zero edge along \[{{l}_{2}}\]. Step II    Start with zero near B. Mark point C at \[{{90}^{o}}\]. Step III Join AC. Then, \[{{l}_{1}}\] is an angle of measure \[{{90}^{o}}\]. Step IV With P as centre and using compasses, draw an arc whose radius is more than half of the length of PQ. Step V With the same radius and with Q as centre, draw another arc in the interior of \[{{l}_{1}}\] which intersects the previous arc at D. Join \[{{l}_{2}}\] Then, \[S\to \] is the required bisector of \[Y\to \]