Answer:
From the given figure, it is clear that AD = AB + BC + CD = 1 + 1 + 1 = 3 units and DG = DE + EF + FG = 1 + 1 + 1 = 3 units Now, AG = AD + DG = 3 + 3 = 6 units and AD = DG = 3 units \[\because \]D lies between A and G. Thus, D is the mid-point of \[\overline{AC}.\]
You need to login to perform this action.
You will be redirected in
3 sec