Heisenberg's Uncertainty Principle
Category : JEE Main & Advanced
This principle states ?It is impossible to specify at any given moment both the position and momentum (velocity) of an electron?.
Mathematically it is represented as , \[\Delta x\,.\,\Delta p\ge \frac{h}{4\pi }\]
Where \[\Delta x=\]uncertainty is position of the particle, \[\Delta p=\] uncertainty in the momentum of the particle
Now since \[\Delta p=m\,\Delta v\]
So equation becomes,\[\Delta x.\,m\Delta v\ge \frac{h}{4\pi }\] or \[\Delta x\,\times \,\Delta v\ge \frac{h}{4\pi m}\]
In terms of uncertainty in energy, \[\Delta E\] and uncertainty in time \[\Delta t,\] this principle is written as, \[\Delta E\,.\,\Delta t\ge \frac{h}{4\pi }\]
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