General Term of an A.P.
Category : JEE Main & Advanced
(1) Let \['a'\] be the first term and \['d'\] be the common difference of an A.P. Then its \[{{n}^{th}}\] term is \[a+(n-1)d\]i.e., \[{{T}_{n}}=a+(n-1)d\].
(2) \[{{p}^{th}}\] term of an A.P. from the end : Let \['a'\] be the first term and \['d'\] be the common difference of an A.P. having \[n\] terms. Then \[{{p}^{th}}\] term from the end is \[{{(n-p+1)}^{th}}\] term from the beginning
i.e., \[{{p}^{th}}\text{ term from the end }=\text{ }{{T}_{(n-p+1)}}=a+(n-p)d\].
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