JEE Main & Advanced Physics NLM, Friction, Circular Motion Motion of Blocks Connected by Mass Less String

Motion of Blocks Connected by Mass Less String

Category : JEE Main & Advanced

   

Condition Free body diagram Equation Tension and acceleration
    \[T={{m}_{1}}a\] \[a=\frac{F}{{{m}_{1}}+{{m}_{2}}}\]
    \[F-T={{m}_{2}}a\] \[T=\frac{{{m}_{1}}F}{{{m}_{1}}+{{m}_{2}}}\]
    \[F-T={{m}_{1}}a\] \[a=\frac{F}{{{m}_{1}}+{{m}_{2}}}\]
    \[T={{m}_{2}}a\] \[T=\frac{{{m}_{2}}F}{{{m}_{1}}+{{m}_{2}}}\]
\[{{T}_{1}}={{m}_{1}}a\] \[a=\frac{F}{{{m}_{1}}+{{m}_{2}}+{{m}_{3}}}\]
      \[{{T}_{2}}-{{T}_{1}}={{m}_{2}}a\] \[{{T}_{1}}=\frac{{{m}_{1}}F}{{{m}_{1}}+{{m}_{2}}+{{m}_{3}}}\]
  \[F-{{T}_{2}}={{m}_{3}}a\] \[{{T}_{2}}=\frac{({{m}_{1}}+{{m}_{2}})F}{{{m}_{1}}+{{m}_{2}}+{{m}_{3}}}\]
    \[F-{{T}_{1}}={{m}_{1}}a\] \[a=\frac{F}{{{m}_{1}}+{{m}_{2}}={{m}_{3}}}\]
    \[{{T}_{1}}-{{T}_{2}}={{m}_{2}}a\] \[{{T}_{1}}=\frac{({{m}_{2}}+{{m}_{3}})F}{{{m}_{1}}+{{m}_{2}}={{m}_{3}}}\]
    \[{{T}_{2}}={{m}_{3}}a\] \[{{T}_{2}}=\frac{{{m}_{3}}F}{{{m}_{1}}+{{m}_{2}}={{m}_{3}}}\]

 

Other Topics


You need to login to perform this action.
You will be redirected in 3 sec spinner

Free
Videos