JEE Main & Advanced Chemistry Hydrocarbons / हाइड्रोकार्बन Bi-phenyl \[{{C}_{6}}{{H}_{5}}\text{ }{{C}_{6}}{{H}_{5}}\]

Bi-phenyl \[{{C}_{6}}{{H}_{5}}\text{ }{{C}_{6}}{{H}_{5}}\]

Category : JEE Main & Advanced

It occurs in coal-tar. It is the simplest example of an aromatic hydrocarbon in which two benzene rings are directly linked to each other.            

 

(1) Methods of formation             

 

(i) Fittig reaction : It consists heating of an ethereal solution of bromobenzene with metallic sodium.

 

            

 

(ii) Ullmann biaryl synthesis : Iodobenzene, on heating with copper in a sealed tube, forms biphenyl. The reaction is facilitated if a strong electron withdrawing group is present in ortho or para position.

 

             

 

(iii) Grignard reaction : Phenyl magnesium bromide reacts with bromo benzene in presence of \[CoC{{l}_{2}}\].            

 

   

 

 

(2) Properties : It is a colourless solid, melting point 71°C. It undergoes usual electrophilic substitution reactions. Since aryl groups are electron withdrawing , they should have deactivating and m-orientating effect. But, it has been experimentally shown that presence of one benzene ring activates the other for electrophilic substitution and directs the incoming group to o- and  p- positions. It has been shown that monosubstitution in the bi-phenyl results in the formation of para isomer as the major product.            

Another special feature of the biphenyl is the behaviour towards second substitution in a monosubstituted biphenyl. The second substituent invariably enters the unsubstituted ring in the ortho and para position no matter what is the nature of substituent already present. 

 

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