Answer:
Refer to page 7/136.
For salt of strong acid and weak base, \[[{{H}_{3}}{{O}^{+}}]\,=\sqrt{\frac{{{K}_{w}}C}{{{K}_{b}}}}\]
Substituting \[\frac{{{K}_{w}}}{{{K}_{b}}}\,={{K}_{h}},\] we get \[[{{H}_{3}}{{O}^{+}}]\,=\sqrt{{{K}_{h}}C}\]
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