Answer:
To have maximum EMF, the anode should have the minimum and cathode should have the maximum \[E{}^\circ \]. Therefore, \[Z{{n}^{2+}}/Zn\] couple should be made as the anode while \[C{{u}^{2+}}/Cu\] couple should be made as the cathode. The cell reaction is: \[Zn(s)+C{{u}^{2+}}(aq)\xrightarrow{\,}Z{{n}^{2+}}(aq)+Cu(s)\]
\[EMF=E{{{}^\circ }_{C{{u}^{2+}}/Cu}}-E{{{}^\circ }_{Z{{n}^{2+}}/Zn}}\]\[=\,+\,0.34\,-(-0.76)=+\,1.1\,V\].
The direction of flow of electrons is from Zn to Cu in the external circuit and from Cu to Zn in the internal circuit. The direction of flow of current is, however, in the reverse direction, i.e., from Cu to Zn in the external circuit and from Zn to Cu in the internal circuit.
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