Answer:
(i) Since \[E{}^\circ \] of Zn is
more negative than that of Fe, therefore, Zn will be oxidised to \[Z{{n}^{2+}}\]
ions while \[F{{e}^{2+}}\] ions will be reduced to Fe. In other words, Fe will
not reduce \[Z{{n}^{2+}}\] ions.
(ii) Since \[E{}^\circ \] of Fe is more
negative than that of Ni, therefore, Fe will be oxidized to \[F{{e}^{2+}}\]
ions while \[N{{i}^{2+}}\] ions will be reduced to Ni. Thus, Fe reduces \[N{{i}^{2+}}\]
ions.
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