11th Class Physics Laws Of Motion / गति के नियम Question Bank 11th CBSE Physics NLM, Friction, Circular Motion

  • question_answer
    The acceleration of a train travelling at 40m/s as it goes round a curve of 160 m in radius is........

    Answer:

                    \[a=\frac{{{\upsilon }^{2}}}{r}=\frac{40\times 40}{160}=\text{ 1}0\text{ m}/{{\text{s}}^{\text{2}}}\]                


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