Answer:
Here, \[s=0,\text{v }=\text{1}00\text{
m}{{\text{s}}^{-\text{1}}};\text{a }=\text{ }-\text{1}0\text{
m}{{\text{s}}^{-\text{2}}},\text{t }=?\]
Using the relation, \[\text{s}=\text{ut
}+\frac{1}{2}\text{a}{{\text{t}}^{\text{2}}}\], we have \[0=\text{1}00\text{t}+~\frac{1}{2}\left(
-\text{1}0 \right){{\text{t}}^{\text{2}}}\]or \[\text{t}=\text{2s}\].
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