Answer:
No ; K.E. of body = \[\frac{1}{2}m{{\upsilon
}^{2}}=\frac{1}{2}m(\overset{\to }{\mathop{\upsilon }}\,,\overset{\to
}{\mathop{\upsilon }}\,)\], which is scalar. In uniform circular motion, speed
of body \[\upsilon \] remains constant, hence K.E. of body remains constant in
uniform circular motion.
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