Answer:
We
know that the slope of the velocity-time graph of an object with time axis is
equal to the acceleration of the object. If a1, a2are the
accelerations of the two objects A and B, then
\[\frac{{{a}_{1}}}{{{a}_{2}}}=\frac{slope\,\,of\,\,v-t\,\,graph\,\,of\,\,object\,A}{slope\,\,of\,v-t\,graph\,\,of\,\,objects\,\,B}=\frac{\tan
{{30}^{o}}}{\tan {{60}^{o}}}=\frac{1/\sqrt{3}}{\sqrt{3}}=\frac{1}{3}\]
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