Answer:
Reaction rate \[=k{{[NO]}^{2}}\,[{{O}_{2}}]\]
Since the volume of the vessel is
reduced to one third (1/3) of the original volume, the concentration of the
reactants per unit volume will become thrice.
Rate with respect to NO will
become nine times.
Rate with respect to \[{{O}_{2}}\]
will become thrice.
Overall reaction rate will
increase to 27 times.
There will no change in the order of the
reaction.
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