Answer:
The relative basic strengths are :
\[\underset{\begin{matrix} (I) \\ {} \\ \end{matrix}}{\mathop{\underset{\begin{smallmatrix} \\ (III) \end{smallmatrix}}{\mathop{CH\equiv CC{{H}_{2}}N{{H}_{2}}}}\,\,\,\,\,\,\,\,<\,\,\,C{{H}_{2}}=CHC{{H}_{2}}N{{H}_{2}}\,\,\,\,\,\,\,<\,\,\,\underset{\begin{smallmatrix} \\ (II) \end{smallmatrix}}{\mathop{C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}N{{H}_{2}}}}\,}}\,\,\]
The electron withdrawing nature of the different groups is :
\[\underset{\begin{smallmatrix} \\ \text{(propargyl-sp}\,\text{hybridised)} \end{smallmatrix}}{\mathop{CH\equiv CCH_{2}^{-}}}\,>\underset{\begin{smallmatrix} \\ \text{(allyl-s}{{\text{p}}^{\text{2}}}\,\text{hybridised)} \end{smallmatrix}}{\mathop{C{{H}_{2}}=CHCH_{2}^{-}}}\,\,\,\,>\underset{\begin{smallmatrix} \\ \text{(n-propyl-s}{{\text{p}}^{\text{3}}}\,\text{hybridised)} \end{smallmatrix}}{\mathop{C{{H}_{3}}C{{H}_{2}}CH_{2}^{-}}}\,\]
In the light of this, the relative order of basic strengths is justified.
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