question_answer1) A polariser is used to [CPMT 1999]
A) Reduce intensity of light done clear
B) Produce polarised light done clear
C) Increase intensity of light done clear
D) Produce unpolarised light done clear
View Solution play_arrowA) Transverse done clear
B) Of high frequency done clear
C) Longitudinal done clear
D) Reflected done clear
View Solution play_arrowA) Interference done clear
B) Refraction done clear
C) Polarisation done clear
D) Reflection done clear
View Solution play_arrowA) \[{{\sin }^{-1}}\sqrt{3}\] done clear
B) \[{{\tan }^{-1}}\sqrt{3}\] done clear
C) \[{{\cos }^{-1}}\sqrt{3}\] done clear
D) \[{{\sin }^{-1}}\frac{1}{\sqrt{3}}\] done clear
View Solution play_arrowA) \[{{\sin }^{-1}}(n)\] done clear
B) \[{{\sin }^{-1}}\left( \frac{1}{n} \right)\] done clear
C) \[{{\tan }^{-1}}\left( \frac{1}{n} \right)\] done clear
D) \[{{\tan }^{-1}}(n)\] done clear
View Solution play_arrowquestion_answer6) Which of following cannot be polarised [Kerala PMT 2001]
A) Radio waves done clear
B) Ultraviolet rays done clear
C) Infrared rays done clear
D) Ultrasonic waves done clear
View Solution play_arrowA) \[{{I}_{0}}\] done clear
B) \[{{I}_{0}}/2\] done clear
C) \[{{I}_{0}}/4\] done clear
D) Zero done clear
View Solution play_arrowA) The intensity of light gradually decreases to zero and remains at zero done clear
B) The intensity of light gradually increases to a maximum and remains at maximum done clear
C) There is no change in intensity done clear
D) The intensity of light is twice maximum and twice zero done clear
View Solution play_arrowquestion_answer9) Out of the following statements which is not correct [CPMT 1991]
A) When unpolarised light passes through a Nicol's prism, the emergent light is elliptically polarized done clear
B) Nicol's prism works on the principle of double refraction and total internal reflection done clear
C) Nicol's prism can be used to produce and analyze polarized light done clear
D) Calcite and Quartz are both doubly refracting crystals done clear
View Solution play_arrowA) \[90+\varphi \] done clear
B) \[{{\sin }^{-1}}(\mu \cos \varphi )\] done clear
C) 90o done clear
D) \[{{90}^{o}}-{{\sin }^{-1}}(\sin \varphi /\mu )\] done clear
View Solution play_arrowA) Vertical plane done clear
B) Horizontal plane done clear
C) Plane making an angle of 45o with the vertical done clear
D) Plane making an angle of 57o with the horizontal done clear
View Solution play_arrowA) The intensity is reduced down to zero and remains zero done clear
B) The intensity reduces down somewhat and rises again done clear
C) There is no change in intensity done clear
D) The intensity gradually reduces to zero and then again increases done clear
View Solution play_arrowquestion_answer13) Polarised glass is used in sun glasses because [CPMT 1981]
A) It reduces the light intensity to half an account of polarisation done clear
B) It is fashionable done clear
C) It has good colour done clear
D) It is cheaper done clear
View Solution play_arrowA) 0o done clear
B) 45o done clear
C) 90o done clear
D) 180o done clear
View Solution play_arrowA) Interference of light done clear
B) Refraction of light done clear
C) Polarisation of light done clear
D) Dispersion of light done clear
View Solution play_arrowA) One dot done clear
B) Two stationary dots done clear
C) Two rotating dots done clear
D) One dot rotating about the other done clear
View Solution play_arrowA) \[A\sqrt{2}\] done clear
B) \[A/\sqrt{2}\] done clear
C) \[\sqrt{3}A/2\] done clear
D) \[A/2\] done clear
View Solution play_arrowA) Both O-ray and E-ray are polarised perpendicular to the plane of incidence done clear
B) Both O-ray and E-ray are polarised in the plane of incidence done clear
C) E-ray is polarised perpendicular to the plane of incidence and O-ray in the plane of incidence done clear
D) E-ray is polarised in the plane of incidence and O-ray perpendicular to the plane of incidence done clear
View Solution play_arrowA) 15? done clear
B) 0? done clear
C) 20? done clear
D) 10? done clear
View Solution play_arrowA) \[{{V}_{o}}\ge {{V}_{E}},\ \ {{\mu }_{o}}\le {{\mu }_{E}}\]if the crystal is calcite done clear
B) \[{{V}_{o}}\le {{V}_{E}},\ \ {{\mu }_{o}}\le {{\mu }_{E}}\]if the crystal is quartz done clear
C) \[{{V}_{o}}\le {{V}_{E}},\ \ {{\mu }_{o}}\ge {{\mu }_{E}}\]if the crystal is calcite done clear
D) \[{{V}_{o}}\ge {{V}_{E}},\ \ {{\mu }_{o}}\ge {{\mu }_{E}}\]if the crystal is quartz done clear
View Solution play_arrowA) 53?4' done clear
B) 126?56' done clear
C) 36?56' done clear
D) 30?4' done clear
View Solution play_arrowA) Varies between a maximum and minimum done clear
B) Becomes zero done clear
C) Does not vary done clear
D) Varies between a maximum and zero done clear
View Solution play_arrowA) A and B are correct done clear
B) A and B are wrong done clear
C) A is correct but B is wrong done clear
D) A is wrong but B is correct done clear
View Solution play_arrowA) 50% done clear
B) 100% done clear
C) 12.5% done clear
D) 37.5% done clear
View Solution play_arrowA) 75? done clear
B) 55? done clear
C) 35? done clear
D) 15? done clear
View Solution play_arrowA) 32 Wm?2 done clear
B) 3 Wm?2 done clear
C) 8 Wm?2 done clear
D) 4 Wm?2 done clear
View Solution play_arrowA) \[+\frac{50{}^\circ }{9}\]per mm done clear
B) \[-\frac{50{}^\circ }{9}\]per mm done clear
C) \[+\frac{9{}^\circ }{50}\]per mm done clear
D) \[-\frac{9{}^\circ }{50}\]per mm done clear
View Solution play_arrowA) Zero done clear
B) \[{{I}_{0}}\] done clear
C) \[\frac{1}{2}{{I}_{0}}\] done clear
D) \[\frac{1}{4}{{I}_{0}}\] done clear
View Solution play_arrowA) Brewster?s law done clear
B) Lambert?s law done clear
C) Malus?s law done clear
D) Bragg?s law done clear
View Solution play_arrowA) Does not change with time done clear
B) Varies periodically with time done clear
C) Increases and decreases linearly with time done clear
D) Is parallel to the direction of propagation done clear
View Solution play_arrowA) Reflected beam is polarised 100 percent done clear
B) Reflected and refracted beams are partially polarised done clear
C) The reason for (a) is that almost all the light is reflected done clear
D) All of the above done clear
View Solution play_arrowquestion_answer32) An optically active compound [DCE 2005]
A) Rotates the plane polarised light done clear
B) Changing the direction of polarised light done clear
C) Do not allow plane polarised light to pass through done clear
D) None of the above done clear
View Solution play_arrowA) \[3\times {{10}^{8}}\] done clear
B) \[\left( \frac{3}{\sqrt{2}} \right)\times {{10}^{8}}\] done clear
C) \[\sqrt{3}\times {{10}^{8}}\] done clear
D) \[0.5\times {{10}^{8}}\] done clear
View Solution play_arrowA) \[\left( \frac{{{I}_{0}}}{8} \right){{\sin }^{2}}2\theta \] done clear
B) \[\left( \frac{{{I}_{0}}}{4} \right){{\sin }^{2}}2\theta \] done clear
C) \[\left( \frac{{{I}_{0}}}{2} \right){{\cos }^{4}}\theta \] done clear
D) \[{{I}_{0}}{{\cos }^{4}}\theta \] done clear
View Solution play_arrowA) Reflection done clear
B) Interference done clear
C) Diffraction done clear
D) Polarisation done clear
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